3x-(4-x)=2(x-8)

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Solution for 3x-(4-x)=2(x-8) equation: 



3x-(4-x)=2(x-8)

We move all terms to the left:

3x-(4-x)-(2(x-8))=0

We add all the numbers together, and all the variables

3x-(-1x+4)-(2(x-8))=0

We get rid of parentheses

3x+1x-(2(x-8))-4=0



We calculate terms in parentheses: -(2(x-8)), so:

2(x-8)

We multiply parentheses

2x-16

Back to the equation:

-(2x-16)



We add all the numbers together, and all the variables

4x-(2x-16)-4=0

We get rid of parentheses

4x-2x+16-4=0

We add all the numbers together, and all the variables

2x+12=0

We move all terms containing x to the left, all other terms to the right

2x=-12

x=-12/2

x=-6

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