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3x-(5x+16)=3-(8x-4)
We move all terms to the left:
3x-(5x+16)-(3-(8x-4))=0
We get rid of parentheses
3x-5x-(3-(8x-4))-16=0
We calculate terms in parentheses: -(3-(8x-4)), so:We add all the numbers together, and all the variables
3-(8x-4)
determiningTheFunctionDomain -(8x-4)+3
We get rid of parentheses
-8x+4+3
We add all the numbers together, and all the variables
-8x+7
Back to the equation:
-(-8x+7)
-2x-(-8x+7)-16=0
We get rid of parentheses
-2x+8x-7-16=0
We add all the numbers together, and all the variables
6x-23=0
We move all terms containing x to the left, all other terms to the right
6x=23
x=23/6
x=3+5/6
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