3x-(5x+3)=7+(3x-2)

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Solution for 3x-(5x+3)=7+(3x-2) equation:



3x-(5x+3)=7+(3x-2)
We move all terms to the left:
3x-(5x+3)-(7+(3x-2))=0
We get rid of parentheses
3x-5x-(7+(3x-2))-3=0
We calculate terms in parentheses: -(7+(3x-2)), so:
7+(3x-2)
determiningTheFunctionDomain (3x-2)+7
We get rid of parentheses
3x-2+7
We add all the numbers together, and all the variables
3x+5
Back to the equation:
-(3x+5)
We add all the numbers together, and all the variables
-2x-(3x+5)-3=0
We get rid of parentheses
-2x-3x-5-3=0
We add all the numbers together, and all the variables
-5x-8=0
We move all terms containing x to the left, all other terms to the right
-5x=8
x=8/-5
x=-1+3/5

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