3x-(8+3x)=7+(4x-3)

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Solution for 3x-(8+3x)=7+(4x-3) equation: 



3x-(8+3x)=7+(4x-3)

We move all terms to the left:

3x-(8+3x)-(7+(4x-3))=0

We add all the numbers together, and all the variables

3x-(3x+8)-(7+(4x-3))=0

We get rid of parentheses

3x-3x-(7+(4x-3))-8=0



We calculate terms in parentheses: -(7+(4x-3)), so:

7+(4x-3)

determiningTheFunctionDomain
(4x-3)+7

We get rid of parentheses

4x-3+7

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

-(4x+4)-8=0

We get rid of parentheses

-4x-4-8=0

We add all the numbers together, and all the variables

-4x-12=0

We move all terms containing x to the left, all other terms to the right

-4x=12

x=12/-4

x=-3

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