3x-(9x-12)=3(4-2x)

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Solution for 3x-(9x-12)=3(4-2x) equation: 



3x-(9x-12)=3(4-2x)

We move all terms to the left:

3x-(9x-12)-(3(4-2x))=0

We add all the numbers together, and all the variables

3x-(9x-12)-(3(-2x+4))=0

We get rid of parentheses

3x-9x-(3(-2x+4))+12=0



We calculate terms in parentheses: -(3(-2x+4)), so:

3(-2x+4)

We multiply parentheses

-6x+12

Back to the equation:

-(-6x+12)



We add all the numbers together, and all the variables

-6x-(-6x+12)+12=0

We get rid of parentheses

-6x+6x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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