3x-(x+1)=2(x+1)+1

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Solution for 3x-(x+1)=2(x+1)+1 equation:


Simplifying
3x + -1(x + 1) = 2(x + 1) + 1

Reorder the terms:
3x + -1(1 + x) = 2(x + 1) + 1
3x + (1 * -1 + x * -1) = 2(x + 1) + 1
3x + (-1 + -1x) = 2(x + 1) + 1

Reorder the terms:
-1 + 3x + -1x = 2(x + 1) + 1

Combine like terms: 3x + -1x = 2x
-1 + 2x = 2(x + 1) + 1

Reorder the terms:
-1 + 2x = 2(1 + x) + 1
-1 + 2x = (1 * 2 + x * 2) + 1
-1 + 2x = (2 + 2x) + 1

Reorder the terms:
-1 + 2x = 2 + 1 + 2x

Combine like terms: 2 + 1 = 3
-1 + 2x = 3 + 2x

Add '-2x' to each side of the equation.
-1 + 2x + -2x = 3 + 2x + -2x

Combine like terms: 2x + -2x = 0
-1 + 0 = 3 + 2x + -2x
-1 = 3 + 2x + -2x

Combine like terms: 2x + -2x = 0
-1 = 3 + 0
-1 = 3

Solving
-1 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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