3x-(x+4)=4(x-2)-6

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Solution for 3x-(x+4)=4(x-2)-6 equation: 



3x-(x+4)=4(x-2)-6

We move all terms to the left:

3x-(x+4)-(4(x-2)-6)=0

We get rid of parentheses

3x-x-(4(x-2)-6)-4=0



We calculate terms in parentheses: -(4(x-2)-6), so:

4(x-2)-6

We multiply parentheses

4x-8-6

We add all the numbers together, and all the variables

4x-14

Back to the equation:

-(4x-14)



We add all the numbers together, and all the variables

2x-(4x-14)-4=0

We get rid of parentheses

2x-4x+14-4=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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