3x-(x-3)=2(x+1)+2

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Solution for 3x-(x-3)=2(x+1)+2 equation:


Simplifying
3x + -1(x + -3) = 2(x + 1) + 2

Reorder the terms:
3x + -1(-3 + x) = 2(x + 1) + 2
3x + (-3 * -1 + x * -1) = 2(x + 1) + 2
3x + (3 + -1x) = 2(x + 1) + 2

Reorder the terms:
3 + 3x + -1x = 2(x + 1) + 2

Combine like terms: 3x + -1x = 2x
3 + 2x = 2(x + 1) + 2

Reorder the terms:
3 + 2x = 2(1 + x) + 2
3 + 2x = (1 * 2 + x * 2) + 2
3 + 2x = (2 + 2x) + 2

Reorder the terms:
3 + 2x = 2 + 2 + 2x

Combine like terms: 2 + 2 = 4
3 + 2x = 4 + 2x

Add '-2x' to each side of the equation.
3 + 2x + -2x = 4 + 2x + -2x

Combine like terms: 2x + -2x = 0
3 + 0 = 4 + 2x + -2x
3 = 4 + 2x + -2x

Combine like terms: 2x + -2x = 0
3 = 4 + 0
3 = 4

Solving
3 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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