3x-(x-5)-5(x-4)=-(x+7)+18

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Solution for 3x-(x-5)-5(x-4)=-(x+7)+18 equation: 



3x-(x-5)-5(x-4)=-(x+7)+18

We move all terms to the left:

3x-(x-5)-5(x-4)-(-(x+7)+18)=0

We multiply parentheses

3x-(x-5)-5x-(-(x+7)+18)+20=0

We get rid of parentheses

3x-x-5x-(-(x+7)+18)+5+20=0



We calculate terms in parentheses: -(-(x+7)+18), so:

-(x+7)+18

We get rid of parentheses

-x-7+18

We add all the numbers together, and all the variables

-1x+11

Back to the equation:

-(-1x+11)



We add all the numbers together, and all the variables

-3x-(-1x+11)+25=0

We get rid of parentheses

-3x+1x-11+25=0

We add all the numbers together, and all the variables

-2x+14=0

We move all terms containing x to the left, all other terms to the right

-2x=-14

x=-14/-2

x=+7

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