3x-(x-8)=2(x+4)

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Solution for 3x-(x-8)=2(x+4) equation:


Simplifying
3x + -1(x + -8) = 2(x + 4)

Reorder the terms:
3x + -1(-8 + x) = 2(x + 4)
3x + (-8 * -1 + x * -1) = 2(x + 4)
3x + (8 + -1x) = 2(x + 4)

Reorder the terms:
8 + 3x + -1x = 2(x + 4)

Combine like terms: 3x + -1x = 2x
8 + 2x = 2(x + 4)

Reorder the terms:
8 + 2x = 2(4 + x)
8 + 2x = (4 * 2 + x * 2)
8 + 2x = (8 + 2x)

Add '-8' to each side of the equation.
8 + -8 + 2x = 8 + -8 + 2x

Combine like terms: 8 + -8 = 0
0 + 2x = 8 + -8 + 2x
2x = 8 + -8 + 2x

Combine like terms: 8 + -8 = 0
2x = 0 + 2x
2x = 2x

Add '-2x' to each side of the equation.
2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 2x + -2x

Combine like terms: 2x + -2x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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