3x-(x-9)+3x=18-2(x+10)

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Solution for 3x-(x-9)+3x=18-2(x+10) equation: 



3x-(x-9)+3x=18-2(x+10)

We move all terms to the left:

3x-(x-9)+3x-(18-2(x+10))=0

We add all the numbers together, and all the variables

6x-(x-9)-(18-2(x+10))=0

We get rid of parentheses

6x-x-(18-2(x+10))+9=0



We calculate terms in parentheses: -(18-2(x+10)), so:

18-2(x+10)

determiningTheFunctionDomain
-2(x+10)+18

We multiply parentheses

-2x-20+18

We add all the numbers together, and all the variables

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

5x-(-2x-2)+9=0

We get rid of parentheses

5x+2x+2+9=0

We add all the numbers together, and all the variables

7x+11=0

We move all terms containing x to the left, all other terms to the right

7x=-11

x=-11/7

x=-1+4/7

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