3x-0.5+5x-2*2=(2x+3*2)+10x-5

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Solution for 3x-0.5+5x-2*2=(2x+3*2)+10x-5 equation: 



3x-0.5+5x-2*2=(2x+3*2)+10x-5

We move all terms to the left:

3x-0.5+5x-2*2-((2x+3*2)+10x-5)=0

We add all the numbers together, and all the variables

3x+5x-((2x+6)+10x-5)-0.5-2*2=0

We add all the numbers together, and all the variables

8x-((2x+6)+10x-5)-4.5=0



We calculate terms in parentheses: -((2x+6)+10x-5), so:

(2x+6)+10x-5

We add all the numbers together, and all the variables

10x+(2x+6)-5

We get rid of parentheses

10x+2x+6-5

We add all the numbers together, and all the variables

12x+1

Back to the equation:

-(12x+1)



We get rid of parentheses

8x-12x-1-4.5=0

We add all the numbers together, and all the variables

-4x-5.5=0

We move all terms containing x to the left, all other terms to the right

-4x=5.5

x=5.5/-4

x=-1+1/2.6666666666667

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