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3x-1+(2x+3/5)=x-4/2
We move all terms to the left:
3x-1+(2x+3/5)-(x-4/2)=0
We add all the numbers together, and all the variables
3x+(+2x+3/5)-(x-2)-1=0
We get rid of parentheses
3x+2x-x+2-1+3/5=0
We multiply all the terms by the denominator
3x*5+2x*5-x*5+3+2*5-1*5=0
We add all the numbers together, and all the variables
3x*5+2x*5-x*5+8=0
Wy multiply elements
15x+10x-5x+8=0
We add all the numbers together, and all the variables
20x+8=0
We move all terms containing x to the left, all other terms to the right
20x=-8
x=-8/20
x=-2/5
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