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3x-1+18/3x=29
We move all terms to the left:
3x-1+18/3x-(29)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
3x+18/3x-30=0
We multiply all the terms by the denominator
3x*3x-30*3x+18=0
Wy multiply elements
9x^2-90x+18=0
a = 9; b = -90; c = +18;
Δ = b2-4ac
Δ = -902-4·9·18
Δ = 7452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7452}=\sqrt{324*23}=\sqrt{324}*\sqrt{23}=18\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-18\sqrt{23}}{2*9}=\frac{90-18\sqrt{23}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+18\sqrt{23}}{2*9}=\frac{90+18\sqrt{23}}{18} $
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