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3x-1/4x=-2
We move all terms to the left:
3x-1/4x-(-2)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
3x-1/4x+2=0
We multiply all the terms by the denominator
3x*4x+2*4x-1=0
Wy multiply elements
12x^2+8x-1=0
a = 12; b = 8; c = -1;
Δ = b2-4ac
Δ = 82-4·12·(-1)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{7}}{2*12}=\frac{-8-4\sqrt{7}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{7}}{2*12}=\frac{-8+4\sqrt{7}}{24} $
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