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3x-1/9x+1=0
Domain of the equation: 9x!=0We multiply all the terms by the denominator
x!=0/9
x!=0
x∈R
3x*9x+1*9x-1=0
Wy multiply elements
27x^2+9x-1=0
a = 27; b = 9; c = -1;
Δ = b2-4ac
Δ = 92-4·27·(-1)
Δ = 189
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{189}=\sqrt{9*21}=\sqrt{9}*\sqrt{21}=3\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{21}}{2*27}=\frac{-9-3\sqrt{21}}{54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{21}}{2*27}=\frac{-9+3\sqrt{21}}{54} $
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