3x-10+4x=-2(x-4)+18

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Solution for 3x-10+4x=-2(x-4)+18 equation: 



3x-10+4x=-2(x-4)+18

We move all terms to the left:

3x-10+4x-(-2(x-4)+18)=0

We add all the numbers together, and all the variables

7x-(-2(x-4)+18)-10=0



We calculate terms in parentheses: -(-2(x-4)+18), so:

-2(x-4)+18

We multiply parentheses

-2x+8+18

We add all the numbers together, and all the variables

-2x+26

Back to the equation:

-(-2x+26)



We get rid of parentheses

7x+2x-26-10=0

We add all the numbers together, and all the variables

9x-36=0

We move all terms containing x to the left, all other terms to the right

9x=36

x=36/9

x=4

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