3x-10+4x=2(x-4)+9

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Solution for 3x-10+4x=2(x-4)+9 equation: 



3x-10+4x=2(x-4)+9

We move all terms to the left:

3x-10+4x-(2(x-4)+9)=0

We add all the numbers together, and all the variables

7x-(2(x-4)+9)-10=0



We calculate terms in parentheses: -(2(x-4)+9), so:

2(x-4)+9

We multiply parentheses

2x-8+9

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

7x-2x-1-10=0

We add all the numbers together, and all the variables

5x-11=0

We move all terms containing x to the left, all other terms to the right

5x=11

x=11/5

x=2+1/5

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