3x-10=2(x+3)+6

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Solution for 3x-10=2(x+3)+6 equation: 



3x-10=2(x+3)+6

We move all terms to the left:

3x-10-(2(x+3)+6)=0



We calculate terms in parentheses: -(2(x+3)+6), so:

2(x+3)+6

We multiply parentheses

2x+6+6

We add all the numbers together, and all the variables

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

3x-2x-12-10=0

We add all the numbers together, and all the variables

x-22=0

We move all terms containing x to the left, all other terms to the right

x=22

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