3x-10x(1+8x)=0

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Solution for 3x-10x(1+8x)=0 equation:



3x-10x(1+8x)=0
We add all the numbers together, and all the variables
3x-10x(8x+1)=0
We multiply parentheses
-80x^2+3x-10x=0
We add all the numbers together, and all the variables
-80x^2-7x=0
a = -80; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·(-80)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*-80}=\frac{0}{-160} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*-80}=\frac{14}{-160} =-7/80 $

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