3x-12+3/7x=2(x-1)

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Solution for 3x-12+3/7x=2(x-1) equation: 



3x-12+3/7x=2(x-1)

We move all terms to the left:

3x-12+3/7x-(2(x-1))=0



Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



We multiply all the terms by the denominator


3x*7x-((2(x-1)))*7x-12*7x+3=0

Wy multiply elements

21x^2-((2(x-1)))*7x-84x+3=0

We add all the numbers together, and all the variables

21x^2-84x-((2(x-1)))*7x+3=0

We move all terms containing x to the left, all other terms to the right

21x^2-84x-((2(x-1)))*7x=-3

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