3x-12+4x+28=10x-29

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Solution for 3x-12+4x+28=10x-29 equation: 



3x-12+4x+28=10x-29

We move all terms to the left:

3x-12+4x+28-(10x-29)=0

We add all the numbers together, and all the variables

7x-(10x-29)+16=0

We get rid of parentheses

7x-10x+29+16=0

We add all the numbers together, and all the variables

-3x+45=0

We move all terms containing x to the left, all other terms to the right

-3x=-45

x=-45/-3

x=+15

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