3x-12+4x=6x+4x-20

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Solution for 3x-12+4x=6x+4x-20 equation: 



3x-12+4x=6x+4x-20

We move all terms to the left:

3x-12+4x-(6x+4x-20)=0

We add all the numbers together, and all the variables

3x+4x-(10x-20)-12=0

We add all the numbers together, and all the variables

7x-(10x-20)-12=0

We get rid of parentheses

7x-10x+20-12=0

We add all the numbers together, and all the variables

-3x+8=0

We move all terms containing x to the left, all other terms to the right

-3x=-8

x=-8/-3

x=2+2/3

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