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3x-12-4x-12=x+3-(x-3)
We move all terms to the left:
3x-12-4x-12-(x+3-(x-3))=0
We add all the numbers together, and all the variables
-1x-(x+3-(x-3))-24=0
We calculate terms in parentheses: -(x+3-(x-3)), so:We add all the numbers together, and all the variables
x+3-(x-3)
determiningTheFunctionDomain x-(x-3)+3
We get rid of parentheses
x-x+3+3
We add all the numbers together, and all the variables
6
Back to the equation:
-(6)
-1x-30=0
We move all terms containing x to the left, all other terms to the right
-x=30
x=30/-1
x=-30
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