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3x-12=2(x+3)+x
We move all terms to the left:
3x-12-(2(x+3)+x)=0
We calculate terms in parentheses: -(2(x+3)+x), so:We get rid of parentheses
2(x+3)+x
We add all the numbers together, and all the variables
x+2(x+3)
We multiply parentheses
x+2x+6
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
3x-3x-6-12=0
We add all the numbers together, and all the variables
-18!=0
There is no solution for this equation
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