3x-12x+6=6x2+10

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Solution for 3x-12x+6=6x2+10 equation: 



3x-12x+6=6x^2+10

We move all terms to the left:

3x-12x+6-(6x^2+10)=0

We add all the numbers together, and all the variables

-9x-(6x^2+10)+6=0

We get rid of parentheses

-6x^2-9x-10+6=0

We add all the numbers together, and all the variables

-6x^2-9x-4=0

a = -6; b = -9; c = -4;
Δ = b2-4ac
Δ = -92-4·(-6)·(-4)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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