3x-13=(x+2)-4(x-7)

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Solution for 3x-13=(x+2)-4(x-7) equation: 



3x-13=(x+2)-4(x-7)

We move all terms to the left:

3x-13-((x+2)-4(x-7))=0



We calculate terms in parentheses: -((x+2)-4(x-7)), so:

(x+2)-4(x-7)

We multiply parentheses

(x+2)-4x+28

We get rid of parentheses

x-4x+2+28

We add all the numbers together, and all the variables

-3x+30

Back to the equation:

-(-3x+30)



We get rid of parentheses

3x+3x-30-13=0

We add all the numbers together, and all the variables

6x-43=0

We move all terms containing x to the left, all other terms to the right

6x=43

x=43/6

x=7+1/6

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