3x-13=7(x+2)-4(x-7)4

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Solution for 3x-13=7(x+2)-4(x-7)4 equation: 



3x-13=7(x+2)-4(x-7)4

We move all terms to the left:

3x-13-(7(x+2)-4(x-7)4)=0



We calculate terms in parentheses: -(7(x+2)-4(x-7)4), so:

7(x+2)-4(x-7)4

We multiply parentheses

7x-16x+14+112

We add all the numbers together, and all the variables

-9x+126

Back to the equation:

-(-9x+126)



We get rid of parentheses

3x+9x-126-13=0

We add all the numbers together, and all the variables

12x-139=0

We move all terms containing x to the left, all other terms to the right

12x=139

x=139/12

x=11+7/12

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