3x-1=(8x-20)*2

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Solution for 3x-1=(8x-20)*2 equation: 



3x-1=(8x-20)*2

We move all terms to the left:

3x-1-((8x-20)*2)=0



We calculate terms in parentheses: -((8x-20)*2), so:

(8x-20)*2

We multiply parentheses

16x-40

Back to the equation:

-(16x-40)



We get rid of parentheses

3x-16x+40-1=0

We add all the numbers together, and all the variables

-13x+39=0

We move all terms containing x to the left, all other terms to the right

-13x=-39

x=-39/-13

x=+3

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