3x-1=8x+9/x+3

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Solution for 3x-1=8x+9/x+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-1 = 8*x+9/x+3 // - 8*x+9/x+3

3*x-(8*x)-(9/x)-3-1 = 0

3*x-8*x-9*x^-1-3-1 = 0

-5*x^1-9*x^-1-4*x^0 = 0

(-5*x^2-4*x^1-9*x^0)/(x^1) = 0 // * x^2

x^1*(-5*x^2-4*x^1-9*x^0) = 0

x^1

-5*x^2-4*x-9 = 0

-5*x^2-4*x-9 = 0

DELTA = (-4)^2-(-9*(-5)*4)

DELTA = -164

DELTA < 0

x in { } 

x belongs to the empty set

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