3x-2(-2x-2)=7+4(4x-4)

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Solution for 3x-2(-2x-2)=7+4(4x-4) equation: 



3x-2(-2x-2)=7+4(4x-4)

We move all terms to the left:

3x-2(-2x-2)-(7+4(4x-4))=0

We multiply parentheses

3x+4x-(7+4(4x-4))+4=0



We calculate terms in parentheses: -(7+4(4x-4)), so:

7+4(4x-4)

determiningTheFunctionDomain
4(4x-4)+7

We multiply parentheses

16x-16+7

We add all the numbers together, and all the variables

16x-9

Back to the equation:

-(16x-9)



We add all the numbers together, and all the variables

7x-(16x-9)+4=0

We get rid of parentheses

7x-16x+9+4=0

We add all the numbers together, and all the variables

-9x+13=0

We move all terms containing x to the left, all other terms to the right

-9x=-13

x=-13/-9

x=1+4/9

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