3x-2(-2x-2)=7+4(4x-4)

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Solution for 3x-2(-2x-2)=7+4(4x-4) equation:



3x-2(-2x-2)=7+4(4x-4)
We move all terms to the left:
3x-2(-2x-2)-(7+4(4x-4))=0
We multiply parentheses
3x+4x-(7+4(4x-4))+4=0
We calculate terms in parentheses: -(7+4(4x-4)), so:
7+4(4x-4)
determiningTheFunctionDomain 4(4x-4)+7
We multiply parentheses
16x-16+7
We add all the numbers together, and all the variables
16x-9
Back to the equation:
-(16x-9)
We add all the numbers together, and all the variables
7x-(16x-9)+4=0
We get rid of parentheses
7x-16x+9+4=0
We add all the numbers together, and all the variables
-9x+13=0
We move all terms containing x to the left, all other terms to the right
-9x=-13
x=-13/-9
x=1+4/9

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