3x-2(-x+13)=-2(x-5)+13x

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Solution for 3x-2(-x+13)=-2(x-5)+13x equation: 



3x-2(-x+13)=-2(x-5)+13x

We move all terms to the left:

3x-2(-x+13)-(-2(x-5)+13x)=0

We add all the numbers together, and all the variables

3x-2(-1x+13)-(-2(x-5)+13x)=0

We multiply parentheses

3x+2x-(-2(x-5)+13x)-26=0



We calculate terms in parentheses: -(-2(x-5)+13x), so:

-2(x-5)+13x

We add all the numbers together, and all the variables

13x-2(x-5)

We multiply parentheses

13x-2x+10

We add all the numbers together, and all the variables

11x+10

Back to the equation:

-(11x+10)



We add all the numbers together, and all the variables

5x-(11x+10)-26=0

We get rid of parentheses

5x-11x-10-26=0

We add all the numbers together, and all the variables

-6x-36=0

We move all terms containing x to the left, all other terms to the right

-6x=36

x=36/-6

x=-6

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