3x-2(1-x)=2(3x-2)

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Solution for 3x-2(1-x)=2(3x-2) equation: 



3x-2(1-x)=2(3x-2)

We move all terms to the left:

3x-2(1-x)-(2(3x-2))=0

We add all the numbers together, and all the variables

3x-2(-1x+1)-(2(3x-2))=0

We multiply parentheses

3x+2x-(2(3x-2))-2=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

5x-(6x-4)-2=0

We get rid of parentheses

5x-6x+4-2=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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