3x-2(1-x)=4(3x-5)+6(3-2x)

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Solution for 3x-2(1-x)=4(3x-5)+6(3-2x) equation: 



3x-2(1-x)=4(3x-5)+6(3-2x)

We move all terms to the left:

3x-2(1-x)-(4(3x-5)+6(3-2x))=0

We add all the numbers together, and all the variables

3x-2(-1x+1)-(4(3x-5)+6(-2x+3))=0

We multiply parentheses

3x+2x-(4(3x-5)+6(-2x+3))-2=0



We calculate terms in parentheses: -(4(3x-5)+6(-2x+3)), so:

4(3x-5)+6(-2x+3)

We multiply parentheses

12x-12x-20+18

We add all the numbers together, and all the variables

-2

Back to the equation:

-(-2)



We add all the numbers together, and all the variables

5x=0

x=0/5

x=0

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