3x-2(2x+3)=3-8

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Solution for 3x-2(2x+3)=3-8 equation: 



3x-2(2x+3)=3-8

We move all terms to the left:

3x-2(2x+3)-(3-8)=0

We add all the numbers together, and all the variables

3x-2(2x+3)-(-5)=0

We add all the numbers together, and all the variables

3x-2(2x+3)+5=0

We multiply parentheses

3x-4x-6+5=0

We add all the numbers together, and all the variables

-1x-1=0

We move all terms containing x to the left, all other terms to the right

-x=1

x=1/-1

x=-1

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