3x-2(2x-5)=2(x+3))-8

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Solution for 3x-2(2x-5)=2(x+3))-8 equation: 



3x-2(2x-5)=2(x+3))-8

We move all terms to the left:

3x-2(2x-5)-(2(x+3))-8)=0

We add all the numbers together, and all the variables

3x-2(2x-5)-(2(x+3))=0

We multiply parentheses

3x-4x-(2(x+3))+10=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

-1x-(2x+6)+10=0

We get rid of parentheses

-1x-2x-6+10=0

We add all the numbers together, and all the variables

-3x+4=0

We move all terms containing x to the left, all other terms to the right

-3x=-4

x=-4/-3

x=1+1/3

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