3x-2(2x-5)=2(x+3)-8-1

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Solution for 3x-2(2x-5)=2(x+3)-8-1 equation: 



3x-2(2x-5)=2(x+3)-8-1

We move all terms to the left:

3x-2(2x-5)-(2(x+3)-8-1)=0

We multiply parentheses

3x-4x-(2(x+3)-8-1)+10=0



We calculate terms in parentheses: -(2(x+3)-8-1), so:

2(x+3)-8-1

We add all the numbers together, and all the variables

2(x+3)-9

We multiply parentheses

2x+6-9

We add all the numbers together, and all the variables

2x-3

Back to the equation:

-(2x-3)



We add all the numbers together, and all the variables

-1x-(2x-3)+10=0

We get rid of parentheses

-1x-2x+3+10=0

We add all the numbers together, and all the variables

-3x+13=0

We move all terms containing x to the left, all other terms to the right

-3x=-13

x=-13/-3

x=4+1/3

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