3x-2(3+4x)=2-(-10+2x)

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Solution for 3x-2(3+4x)=2-(-10+2x) equation: 



3x-2(3+4x)=2-(-10+2x)

We move all terms to the left:

3x-2(3+4x)-(2-(-10+2x))=0

We add all the numbers together, and all the variables

3x-2(4x+3)-(2-(2x-10))=0

We multiply parentheses

3x-8x-(2-(2x-10))-6=0



We calculate terms in parentheses: -(2-(2x-10)), so:

2-(2x-10)

determiningTheFunctionDomain
-(2x-10)+2

We get rid of parentheses

-2x+10+2

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We add all the numbers together, and all the variables

-5x-(-2x+12)-6=0

We get rid of parentheses

-5x+2x-12-6=0

We add all the numbers together, and all the variables

-3x-18=0

We move all terms containing x to the left, all other terms to the right

-3x=18

x=18/-3

x=-6

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