3x-2(3-4x)=3(x-5)-7

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Solution for 3x-2(3-4x)=3(x-5)-7 equation: 



3x-2(3-4x)=3(x-5)-7

We move all terms to the left:

3x-2(3-4x)-(3(x-5)-7)=0

We add all the numbers together, and all the variables

3x-2(-4x+3)-(3(x-5)-7)=0

We multiply parentheses

3x+8x-(3(x-5)-7)-6=0



We calculate terms in parentheses: -(3(x-5)-7), so:

3(x-5)-7

We multiply parentheses

3x-15-7

We add all the numbers together, and all the variables

3x-22

Back to the equation:

-(3x-22)



We add all the numbers together, and all the variables

11x-(3x-22)-6=0

We get rid of parentheses

11x-3x+22-6=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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