3x-2(3-4x)=4(x-5)-21

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Solution for 3x-2(3-4x)=4(x-5)-21 equation: 



3x-2(3-4x)=4(x-5)-21

We move all terms to the left:

3x-2(3-4x)-(4(x-5)-21)=0

We add all the numbers together, and all the variables

3x-2(-4x+3)-(4(x-5)-21)=0

We multiply parentheses

3x+8x-(4(x-5)-21)-6=0



We calculate terms in parentheses: -(4(x-5)-21), so:

4(x-5)-21

We multiply parentheses

4x-20-21

We add all the numbers together, and all the variables

4x-41

Back to the equation:

-(4x-41)



We add all the numbers together, and all the variables

11x-(4x-41)-6=0

We get rid of parentheses

11x-4x+41-6=0

We add all the numbers together, and all the variables

7x+35=0

We move all terms containing x to the left, all other terms to the right

7x=-35

x=-35/7

x=-5

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