3x-2(3x+23)-223+32=34(x-4)+349

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Solution for 3x-2(3x+23)-223+32=34(x-4)+349 equation: 



3x-2(3x+23)-223+32=34(x-4)+349

We move all terms to the left:

3x-2(3x+23)-223+32-(34(x-4)+349)=0

We add all the numbers together, and all the variables

3x-2(3x+23)-(34(x-4)+349)-191=0

We multiply parentheses

3x-6x-(34(x-4)+349)-46-191=0



We calculate terms in parentheses: -(34(x-4)+349), so:

34(x-4)+349

We multiply parentheses

34x-136+349

We add all the numbers together, and all the variables

34x+213

Back to the equation:

-(34x+213)



We add all the numbers together, and all the variables

-3x-(34x+213)-237=0

We get rid of parentheses

-3x-34x-213-237=0

We add all the numbers together, and all the variables

-37x-450=0

We move all terms containing x to the left, all other terms to the right

-37x=450

x=450/-37

x=-12+6/37

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