3x-2(4+x)+15=2(x-3)+7

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Solution for 3x-2(4+x)+15=2(x-3)+7 equation: 



3x-2(4+x)+15=2(x-3)+7

We move all terms to the left:

3x-2(4+x)+15-(2(x-3)+7)=0

We add all the numbers together, and all the variables

3x-2(x+4)-(2(x-3)+7)+15=0

We multiply parentheses

3x-2x-(2(x-3)+7)-8+15=0



We calculate terms in parentheses: -(2(x-3)+7), so:

2(x-3)+7

We multiply parentheses

2x-6+7

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We add all the numbers together, and all the variables

x-(2x+1)+7=0

We get rid of parentheses

x-2x-1+7=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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