3x-2(4x+10)=10+4(4x-8)

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Solution for 3x-2(4x+10)=10+4(4x-8) equation: 



3x-2(4x+10)=10+4(4x-8)

We move all terms to the left:

3x-2(4x+10)-(10+4(4x-8))=0

We multiply parentheses

3x-8x-(10+4(4x-8))-20=0



We calculate terms in parentheses: -(10+4(4x-8)), so:

10+4(4x-8)

determiningTheFunctionDomain
4(4x-8)+10

We multiply parentheses

16x-32+10

We add all the numbers together, and all the variables

16x-22

Back to the equation:

-(16x-22)



We add all the numbers together, and all the variables

-5x-(16x-22)-20=0

We get rid of parentheses

-5x-16x+22-20=0

We add all the numbers together, and all the variables

-21x+2=0

We move all terms containing x to the left, all other terms to the right

-21x=-2

x=-2/-21

x=2/21

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