3x-2(4x+3)-(x+5)=6-(2x+)

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Solution for 3x-2(4x+3)-(x+5)=6-(2x+) equation: 



3x-2(4x+3)-(x+5)=6-(2x+)

We move all terms to the left:

3x-2(4x+3)-(x+5)-(6-(2x+))=0

We add all the numbers together, and all the variables

3x-2(4x+3)-(x+5)-(6-(+2x))=0

We multiply parentheses

3x-8x-(x+5)-(6-(+2x))-6=0

We get rid of parentheses

3x-8x-x-(6-(+2x))-5-6=0



We calculate terms in parentheses: -(6-(+2x)), so:

6-(+2x)

determiningTheFunctionDomain
-(+2x)+6

We get rid of parentheses

-2x+6

Back to the equation:

-(-2x+6)



We add all the numbers together, and all the variables

-6x-(-2x+6)-11=0

We get rid of parentheses

-6x+2x-6-11=0

We add all the numbers together, and all the variables

-4x-17=0

We move all terms containing x to the left, all other terms to the right

-4x=17

x=17/-4

x=-4+1/4

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