3x-2(4x-2)=6x+20

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Solution for 3x-2(4x-2)=6x+20 equation: 



3x-2(4x-2)=6x+20

We move all terms to the left:

3x-2(4x-2)-(6x+20)=0

We multiply parentheses

3x-8x-(6x+20)+4=0

We get rid of parentheses

3x-8x-6x-20+4=0

We add all the numbers together, and all the variables

-11x-16=0

We move all terms containing x to the left, all other terms to the right

-11x=16

x=16/-11

x=-1+5/11

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