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3x-2(5x+1)=4(x-)
We move all terms to the left:
3x-2(5x+1)-(4(x-))=0
We add all the numbers together, and all the variables
3x-2(5x+1)-(4(+x))=0
We multiply parentheses
3x-10x-(4(+x))-2=0
We calculate terms in parentheses: -(4(+x)), so:We add all the numbers together, and all the variables
4(+x)
We multiply parentheses
4x
Back to the equation:
-(4x)
-11x-2=0
We move all terms containing x to the left, all other terms to the right
-11x=2
x=2/-11
x=-2/11
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