3x-2(5x-8)=9-4(3x+7)

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Solution for 3x-2(5x-8)=9-4(3x+7) equation: 



3x-2(5x-8)=9-4(3x+7)

We move all terms to the left:

3x-2(5x-8)-(9-4(3x+7))=0

We multiply parentheses

3x-10x-(9-4(3x+7))+16=0



We calculate terms in parentheses: -(9-4(3x+7)), so:

9-4(3x+7)

determiningTheFunctionDomain
-4(3x+7)+9

We multiply parentheses

-12x-28+9

We add all the numbers together, and all the variables

-12x-19

Back to the equation:

-(-12x-19)



We add all the numbers together, and all the variables

-7x-(-12x-19)+16=0

We get rid of parentheses

-7x+12x+19+16=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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