3x-2(6-2x)=5+3(2x-1)

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Solution for 3x-2(6-2x)=5+3(2x-1) equation: 



3x-2(6-2x)=5+3(2x-1)

We move all terms to the left:

3x-2(6-2x)-(5+3(2x-1))=0

We add all the numbers together, and all the variables

3x-2(-2x+6)-(5+3(2x-1))=0

We multiply parentheses

3x+4x-(5+3(2x-1))-12=0



We calculate terms in parentheses: -(5+3(2x-1)), so:

5+3(2x-1)

determiningTheFunctionDomain
3(2x-1)+5

We multiply parentheses

6x-3+5

We add all the numbers together, and all the variables

6x+2

Back to the equation:

-(6x+2)



We add all the numbers together, and all the variables

7x-(6x+2)-12=0

We get rid of parentheses

7x-6x-2-12=0

We add all the numbers together, and all the variables

x-14=0

We move all terms containing x to the left, all other terms to the right

x=14

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