3x-2(6-x)=7x+2(5+x)=-6

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Solution for 3x-2(6-x)=7x+2(5+x)=-6 equation: 



3x-2(6-x)=7x+2(5+x)=-6

We move all terms to the left:

3x-2(6-x)-(7x+2(5+x))=0

We add all the numbers together, and all the variables

3x-2(-1x+6)-(7x+2(x+5))=0

We multiply parentheses

3x+2x-(7x+2(x+5))-12=0



We calculate terms in parentheses: -(7x+2(x+5)), so:

7x+2(x+5)

We multiply parentheses

7x+2x+10

We add all the numbers together, and all the variables

9x+10

Back to the equation:

-(9x+10)



We add all the numbers together, and all the variables

5x-(9x+10)-12=0

We get rid of parentheses

5x-9x-10-12=0

We add all the numbers together, and all the variables

-4x-22=0

We move all terms containing x to the left, all other terms to the right

-4x=22

x=22/-4

x=-5+1/2

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