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3x-2(7x-1)=3(x+1)-5(3x-8)
We move all terms to the left:
3x-2(7x-1)-(3(x+1)-5(3x-8))=0
We multiply parentheses
3x-14x-(3(x+1)-5(3x-8))+2=0
We calculate terms in parentheses: -(3(x+1)-5(3x-8)), so:We add all the numbers together, and all the variables
3(x+1)-5(3x-8)
We multiply parentheses
3x-15x+3+40
We add all the numbers together, and all the variables
-12x+43
Back to the equation:
-(-12x+43)
-11x-(-12x+43)+2=0
We get rid of parentheses
-11x+12x-43+2=0
We add all the numbers together, and all the variables
x-41=0
We move all terms containing x to the left, all other terms to the right
x=41
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